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How to calculate required electric connection in KVA
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<blockquote data-quote="Justinâ„¢" data-source="post: 1052901" data-attributes="member: 3124"><p>^^ Won't solve it.</p><p></p><p>To make it even more easy:</p><p>The builder will install a Miniature Circuit Breaker (MCB) of the total load. My load increases, the MCB will trip. I want to know the required MCB to be installed so that I can use 7 tube-lights, 7 Fans, 3 TVs, 1 Refrigerator and 2 ACs to run without tripping the MCB.</p><p></p><p>Just to add: I am not an Electrical Engineer (as would be very obvious from my question <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite7" alt=":p" title="Stick Out Tongue :p" loading="lazy" data-shortname=":p" />), I also don't know the intricate details I must provide for this question. But I do know that one TV can take more load than another and a 1.5 Ton AC will take less load than a 2.0 Ton AC. So anybody replying can answer in general terms.</p></blockquote><p></p>
[QUOTE="Justinâ„¢, post: 1052901, member: 3124"] ^^ Won't solve it. To make it even more easy: The builder will install a Miniature Circuit Breaker (MCB) of the total load. My load increases, the MCB will trip. I want to know the required MCB to be installed so that I can use 7 tube-lights, 7 Fans, 3 TVs, 1 Refrigerator and 2 ACs to run without tripping the MCB. Just to add: I am not an Electrical Engineer (as would be very obvious from my question :P), I also don't know the intricate details I must provide for this question. But I do know that one TV can take more load than another and a 1.5 Ton AC will take less load than a 2.0 Ton AC. So anybody replying can answer in general terms. [/QUOTE]
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How to calculate required electric connection in KVA
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