Hi,
I have a doubt with the TCP IP Port assignment & connection. ACtually,read abt it in coll....but then....now my brain doesnt remember much of the stuff.
ANyways..here is my doubt:
1. I have a Server which is hosting a streaming service on Port:80(just for an example).
Assume the URL to connect is :10.148.20.1:80
2. I have many clients arnd the world who would need to access this site and view the streaming video online.
3.I want to know if Port:80 would be used only for Connection establishment from the clients to the server or would data transfer also occur through port:80???
4.If POrt:80 is used only for connec establishment then is it that for each client there would be a separate port assigned on the SERVER for data transfer between the client & server.
5.If there are going to separate ports assigned for each client then would the server not be limited to serving just 65536 clients at a time??
Note:I believe 65536 is the max no.of ports in a comp.
Any help on this would be much appreciated.
Thanks
Ashwin.
I have a doubt with the TCP IP Port assignment & connection. ACtually,read abt it in coll....but then....now my brain doesnt remember much of the stuff.
ANyways..here is my doubt:
1. I have a Server which is hosting a streaming service on Port:80(just for an example).
Assume the URL to connect is :10.148.20.1:80
2. I have many clients arnd the world who would need to access this site and view the streaming video online.
3.I want to know if Port:80 would be used only for Connection establishment from the clients to the server or would data transfer also occur through port:80???
4.If POrt:80 is used only for connec establishment then is it that for each client there would be a separate port assigned on the SERVER for data transfer between the client & server.
5.If there are going to separate ports assigned for each client then would the server not be limited to serving just 65536 clients at a time??
Note:I believe 65536 is the max no.of ports in a comp.
Any help on this would be much appreciated.
Thanks
Ashwin.