chiragsthakur
Explorer
You think you know more then kindly explain this calculation.....
Let me explain:
Acc to definition, Output power/input power * 100 = efficiency (%) The definition itself clears the whole doubt you have. Efficiency in our case is given, output power is given...So it calculates the input power only... How will you determine output power from efficiency and this equation..??/ You have any answer??? You shouldnt have any, and thats my bet...
Now If I manufacture a PSU and rate it as capable of giving 500W output and 80% efficient, then does the definition say that my PSU is capable of delivering 80% of my rated output???? i.e 80/100*500=400W ?? Answer is NO.
It means it will suck in (100%-80%)=20% more power from AC socket to convert it to 500w. (approximate values, true values can differ according to various losses) Oh yes... Do you know what losses are??
(The above are full load calculations i.e if your system is sucking out 500w from 500w PSU, ideal case, not practical)
So get your basics right about efficiency and power calculations
I hope I am clear. Further explanation can be given on request
you are making a mess of calculations here and asking what wrong you are saying... Come on man you are saying if a 500W PSU is 50% efficient then it will give out only 50/100*500=250w???vaibhav1 said:because if your PSU is not 80 plus then you are already putting a lot of strain on it, the psu's which are not 80 plus they can only be good upto 50 - 60 percent more than that can cause problem or it may even blow up, so you have 500 watts 50% of 500 is 250 so just think that single 6850 is more than enough for that PSU.
Let me explain:
Acc to definition, Output power/input power * 100 = efficiency (%) The definition itself clears the whole doubt you have. Efficiency in our case is given, output power is given...So it calculates the input power only... How will you determine output power from efficiency and this equation..??/ You have any answer??? You shouldnt have any, and thats my bet...
Now If I manufacture a PSU and rate it as capable of giving 500W output and 80% efficient, then does the definition say that my PSU is capable of delivering 80% of my rated output???? i.e 80/100*500=400W ?? Answer is NO.
It means it will suck in (100%-80%)=20% more power from AC socket to convert it to 500w. (approximate values, true values can differ according to various losses) Oh yes... Do you know what losses are??
(The above are full load calculations i.e if your system is sucking out 500w from 500w PSU, ideal case, not practical)
So get your basics right about efficiency and power calculations
I hope I am clear. Further explanation can be given on request